What is the value of sin(100)cos(40)-cos(100)sin(40) ?

The value of sin(100)cos(40)-cos(100)sin(40) is (sqrt(3))/2

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sin(100)cos(40)-cos(100)sin(40)

sin (10 0^{\circ}) cos (4 0^{\circ}) - cos (10 0^{\circ}) sin (4 0^{\circ})

\frac{3}{2}

Solution steps

sin (10 0^{\circ}) cos (4 0^{\circ}) - cos (10 0^{\circ}) sin (4 0^{\circ})

Rewrite using trig identities:

sin (6 0^{\circ})

= sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

= \frac{3}{2}

cos (0^{2})

\frac{2}{sin ( 4 5 ^{\circ} )}

tan (0.25)

cos^{2} (7)

csc (- \frac{10 π}{3})

What is the value of sin(100)cos(40)-cos(100)sin(40) ?
The value of sin(100)cos(40)-cos(100)sin(40) is (sqrt(3))/2