What is the general solution for cot(θ)=(sqrt(13))/6 ?

The general solution for cot(θ)=(sqrt(13))/6 is θ=1.02969…+pin

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cot(θ)=(sqrt(13))/6

cot (θ) = \frac{13}{6}

θ = 1.02969 \dots + πn

Solution steps

cot (θ) = \frac{13}{6}

Apply trig inverse properties

θ = arccot (\frac{13}{6}) + πn

Show solutions in decimal form

θ = 1.02969 \dots + πn

cos (θ) = \frac{2}{6}

2 \cdot cos^{2} (x) = 1

cos^{2} (x) = \frac{1}{6}

x, z = arccos (x + y)

3 tan (x) - 2 cot (x) = 5

What is the general solution for cot(θ)=(sqrt(13))/6 ?
The general solution for cot(θ)=(sqrt(13))/6 is θ=1.02969…+pin