What is the general solution for cos(B)= 12/13 ?

The general solution for cos(B)= 12/13 is B=0.39479…+2pin,B=2pi-0.39479…+2pin

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cos(B)= 12/13

cos (B) = \frac{12}{13}

B = 0.39479 \dots + 2 πn, B = 2 π - 0.39479 \dots + 2 πn

Solution steps

cos (B) = \frac{12}{13}

Apply trig inverse properties

B = arccos (\frac{12}{13}) + 2 πn, B = 2 π - arccos (\frac{12}{13}) + 2 πn

Show solutions in decimal form

B = 0.39479 \dots + 2 πn, B = 2 π - 0.39479 \dots + 2 πn

sin (θ) = \frac{2}{9}, θ, 3 r (θ, d) d, tan (2 θ)

sin (\frac{x}{2}) = 0, 0 \leq x \leq 2 π

sin (11 0^{\circ} - \frac{x}{2}) = - sin (7 0^{\circ})

(2 sin (x) - 1) (sin (x) + 0.5) = 0

tan (θ) - 2 cos (θ) tan (θ) = 0

What is the general solution for cos(B)= 12/13 ?
The general solution for cos(B)= 12/13 is B=0.39479…+2pin,B=2pi-0.39479…+2pin