What is the general solution for sqrt(3)tan(2x-pi)+1=0 ?

The general solution for sqrt(3)tan(2x-pi)+1=0 is x= pi/2+(5pi}{12}+\frac{pin)/2

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sqrt(3)tan(2x-pi)+1=0

3 tan (2 x - π) + 1 = 0

x = \frac{π}{2} + \frac{5 π}{12} + \frac{πn}{2}

Solution steps

3 tan (2 x - π) + 1 = 0

Move

1

to the right side

3 tan (2 x - π) = - 1

Divide both sides by

3

tan (2 x - π) = - \frac{3}{3}

General solutions for

tan (2 x - π) = - \frac{3}{3}

2 x - π = \frac{5 π}{6} + πn

Solve

2 x - π = \frac{5 π}{6} + πn : x = \frac{π}{2} + \frac{5 π}{12} + \frac{πn}{2}

x = \frac{π}{2} + \frac{5 π}{12} + \frac{πn}{2}

\frac{7}{4} cos (3 θ) - 1 = 0

cos (x) = sin (\frac{7 π}{6}), 0 \leq x \leq 2 π

cos (2 x) = \frac{( 3 k - 3 )}{8}

1.5 = 2.75 cos (30 (x - 4)) + 3.25

sin (x) = (\frac{5}{12})

What is the general solution for sqrt(3)tan(2x-pi)+1=0 ?
The general solution for sqrt(3)tan(2x-pi)+1=0 is x= pi/2+(5pi}{12}+\frac{pin)/2