What is the general solution for solvefor θ,1+cos(θ)=3cos(θ) ?

The general solution for solvefor θ,1+cos(θ)=3cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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solvefor θ,1+cos(θ)=3cos(θ)

solve for

θ, 1 + cos (θ) = 3 cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

1 + cos (θ) = 3 cos (θ)

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

3 sin (x) - 4 cos (x) = 0

sin (θ) = \frac{1}{4}, 0^{\circ} < θ < 9 0^{\circ}

sin (90 - 2 x) = cos (9 0^{\circ} - x)

tan (\frac{x}{2}) = - 0.39

4 sin (3 x) - 1 = 0

What is the general solution for solvefor θ,1+cos(θ)=3cos(θ) ?
The general solution for solvefor θ,1+cos(θ)=3cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin