What is the general solution for sin(a)=0.9455 ?

The general solution for sin(a)=0.9455 is a=1.23912…+2pin,a=pi-1.23912…+2pin

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sin(a)=0.9455

sin (a) = 0.9455

a = 1.23912 \dots + 2 πn, a = π - 1.23912 \dots + 2 πn

Solution steps

sin (a) = 0.9455

Apply trig inverse properties

a = arcsin (0.9455) + 2 πn, a = π - arcsin (0.9455) + 2 πn

Show solutions in decimal form

a = 1.23912 \dots + 2 πn, a = π - 1.23912 \dots + 2 πn

x, \frac{sin ( x )}{5} = \frac{sin ( 12 5 ^{\circ} )}{20}

2 - 2 sin^{2} (x) = 0

sin (x) = \frac{2.5}{3}

tan (θ) + cot (θ) = 1

sin (θ) = - \frac{1}{2}, 0 \leq θ < 2 π

What is the general solution for sin(a)=0.9455 ?
The general solution for sin(a)=0.9455 is a=1.23912…+2pin,a=pi-1.23912…+2pin