What is the general solution for (2cos(x))-1=0 ?

The general solution for (2cos(x))-1=0 is x= pi/3+2pin,x=(5pi)/3+2pin

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(2cos(x))-1=0

(2 cos (x)) - 1 = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

(2 cos (x)) - 1 = 0

Move

1

to the right side

2 cos (x) = 1

Divide both sides by

2

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

3 cos (x) = sin^{2} (x)

sin (θ) = \frac{5 π}{3}

10 cos (θ) = 8

cos (θ) = \frac{- 18}{20 \cdot 26}

sin (2 x) = - cos (x), 0 \leq x \leq 2 π

What is the general solution for (2cos(x))-1=0 ?
The general solution for (2cos(x))-1=0 is x= pi/3+2pin,x=(5pi)/3+2pin