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Popular Trigonometry >

0=5*sin(2pi*(-0.25-x))

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Solution

0=5⋅sin(2π⋅(−0.25−x))

Solution

x=−n−0.25,x=−n−0.75
+1
Degrees
x=−14.32394…∘−57.29577…∘n,x=−42.97183…∘−57.29577…∘n
Solution steps
0=5sin(2π(−0.25−x))
Switch sides5sin(2π(−0.25−x))=0
Divide both sides by 5
5sin(2π(−0.25−x))=0
Divide both sides by 555sin(2π(−0.25−x))​=50​
Simplifysin(2π(−0.25−x))=0
sin(2π(−0.25−x))=0
General solutions for sin(2π(−0.25−x))=0
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
2π(−0.25−x)=0+2πn,2π(−0.25−x)=π+2πn
2π(−0.25−x)=0+2πn,2π(−0.25−x)=π+2πn
Solve 2π(−0.25−x)=0+2πn:x=−n−0.25
2π(−0.25−x)=0+2πn
0+2πn=2πn2π(−0.25−x)=2πn
Divide both sides by 2π
2π(−0.25−x)=2πn
Divide both sides by 2π2π2π(−0.25−x)​=2π2πn​
Simplify
2π2π(−0.25−x)​=2π2πn​
Simplify 2π2π(−0.25−x)​:−0.25−x
2π2π(−0.25−x)​
Divide the numbers: 22​=1=ππ(−x−0.25)​
Cancel the common factor: π=−0.25−x
Simplify 2π2πn​:n
2π2πn​
Divide the numbers: 22​=1=ππn​
Cancel the common factor: π=n
−0.25−x=n
−0.25−x=n
−0.25−x=n
Move 0.25to the right side
−0.25−x=n
Add 0.25 to both sides−0.25−x+0.25=n+0.25
Simplify−x=n+0.25
−x=n+0.25
Divide both sides by −1
−x=n+0.25
Divide both sides by −1−1−x​=−1n​+−10.25​
Simplify
−1−x​=−1n​+−10.25​
Simplify −1−x​:x
−1−x​
Apply the fraction rule: −b−a​=ba​=1x​
Apply rule 1a​=a=x
Simplify −1n​+−10.25​:−n−0.25
−1n​+−10.25​
−1n​=−n
−1n​
Apply the fraction rule: −ba​=−ba​=−1n​
Apply rule 1a​=a=−n
=−n+−10.25​
−10.25​=−0.25
−10.25​
Apply the fraction rule: −ba​=−ba​=−10.25​
Apply rule 1a​=a=−0.25
=−n−0.25
x=−n−0.25
x=−n−0.25
x=−n−0.25
Solve 2π(−0.25−x)=π+2πn:x=−n−0.75
2π(−0.25−x)=π+2πn
Divide both sides by 2π
2π(−0.25−x)=π+2πn
Divide both sides by 2π2π2π(−0.25−x)​=2ππ​+2π2πn​
Simplify
2π2π(−0.25−x)​=2ππ​+2π2πn​
Simplify 2π2π(−0.25−x)​:−0.25−x
2π2π(−0.25−x)​
Divide the numbers: 22​=1=ππ(−x−0.25)​
Cancel the common factor: π=−0.25−x
Simplify 2ππ​+2π2πn​:21​+n
2ππ​+2π2πn​
Cancel 2ππ​:21​
2ππ​
Cancel the common factor: π=21​
=21​+2π2πn​
Cancel 2π2πn​:n
2π2πn​
Cancel 2π2πn​:n
2π2πn​
Divide the numbers: 22​=1=ππn​
Cancel the common factor: π=n
=n
=21​+n
−0.25−x=21​+n
−0.25−x=21​+n
−0.25−x=21​+n
Move 0.25to the right side
−0.25−x=21​+n
Add 0.25 to both sides−0.25−x+0.25=21​+n+0.25
Simplify
−0.25−x+0.25=21​+n+0.25
Simplify −0.25−x+0.25:−x
−0.25−x+0.25
Add similar elements: −0.25+0.25=0
=−x
Simplify 21​+n+0.25:n+0.75
21​+n+0.25
Convert element to a decimal form21​=0.5=0.5+n+0.25
Add the numbers: 0.5+0.25=0.75=n+0.75
−x=n+0.75
−x=n+0.75
−x=n+0.75
Divide both sides by −1
−x=n+0.75
Divide both sides by −1−1−x​=−1n​+−10.75​
Simplify
−1−x​=−1n​+−10.75​
Simplify −1−x​:x
−1−x​
Apply the fraction rule: −b−a​=ba​=1x​
Apply rule 1a​=a=x
Simplify −1n​+−10.75​:−n−0.75
−1n​+−10.75​
−1n​=−n
−1n​
Apply the fraction rule: −ba​=−ba​=−1n​
Apply rule 1a​=a=−n
=−n+−10.75​
−10.75​=−0.75
−10.75​
Apply the fraction rule: −ba​=−ba​=−10.75​
Apply rule 1a​=a=−0.75
=−n−0.75
x=−n−0.75
x=−n−0.75
x=−n−0.75
x=−n−0.25,x=−n−0.75

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Frequently Asked Questions (FAQ)

  • What is the general solution for 0=5*sin(2pi*(-0.25-x)) ?

    The general solution for 0=5*sin(2pi*(-0.25-x)) is x=-n-0.25,x=-n-0.75
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