What is the value of sin^2(30)+cos^2(60) ?

The value of sin^2(30)+cos^2(60) is 1/2

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sin^2(30)+cos^2(60)

sin^{2} (3 0^{\circ}) + cos^{2} (6 0^{\circ})

\frac{1}{2}

Solution steps

sin^{2} (3 0^{\circ}) + cos^{2} (6 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

= (\frac{1}{2})^{2} + (\frac{1}{2})^{2}

Simplify

(\frac{1}{2})^{2} + (\frac{1}{2})^{2} : \frac{1}{2}

= \frac{1}{2}

\frac{tan ( 7 8 ^{\circ} ) - tan ( 1 8 ^{\circ} )}{1 + tan ( 7 8 ^{\circ} ) tan ( 1 8 ^{\circ} )}

sec (\frac{π}{8}) - \frac{1}{( \frac{π}{8} ) ^{3}} + 5

\frac{3.7}{cos ( 6 4 ^{\circ} )}

sin (2 (π))

arccos (\frac{4.6}{8.6})

What is the value of sin^2(30)+cos^2(60) ?
The value of sin^2(30)+cos^2(60) is 1/2