What is the value of cot(-30)+tan(600)-csc(-450) ?

The value of cot(-30)+tan(600)-csc(-450) is 1

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cot(-30)+tan(600)-csc(-450)

cot (- 3 0^{\circ}) + tan (60 0^{\circ}) - csc (- 45 0^{\circ})

1

Solution steps

cot (- 3 0^{\circ}) + tan (60 0^{\circ}) - csc (- 45 0^{\circ})

Use the following property:

csc (- x) = - csc (x)

csc (- 45 0^{\circ}) = - csc (45 0^{\circ})

= cot (- 3 0^{\circ}) + tan (60 0^{\circ}) - (- csc (45 0^{\circ}))

Use the following property:

cot (- x) = - cot (x)

cot (- 3 0^{\circ}) = - cot (3 0^{\circ})

= - cot (3 0^{\circ}) + tan (60 0^{\circ}) - (- csc (45 0^{\circ}))

tan (60 0^{\circ}) = tan (6 0^{\circ})

= - cot (3 0^{\circ}) + tan (6 0^{\circ}) - (- csc (45 0^{\circ}))

csc (45 0^{\circ}) = csc (9 0^{\circ})

= - cot (3 0^{\circ}) + tan (6 0^{\circ}) - (- csc (9 0^{\circ}))

Simplify

= - cot (3 0^{\circ}) + tan (6 0^{\circ}) + csc (9 0^{\circ})

Use the following trivial identity:

cot (3 0^{\circ}) = 3

Use the following trivial identity:

tan (6 0^{\circ}) = 3

Use the following trivial identity:

csc (9 0^{\circ}) = 1

= - 3 + 3 + 1

Simplify

= 1

cos (\frac{5 π}{4})

cos^{2} (\frac{π}{2})

arcsin (\frac{3}{2})

cos^{2} (x) - sin^{2} (x) = 1 - 2 sin^{2} (x)

sin (24 0^{\circ})

What is the value of cot(-30)+tan(600)-csc(-450) ?
The value of cot(-30)+tan(600)-csc(-450) is 1