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Popular >

2cos^2(x)+3cos(x)+1=0,0<= x<2pi

Solution

2 cos^{2} (x) + 3 cos (x) + 1 = 0, 0 \leq x < 2 π

Solution

x = \frac{2 π}{3}, x = \frac{4 π}{3}, x = π

+1

Solution steps

2 cos^{2} (x) + 3 cos (x) + 1 = 0, 0 \leq x < 2 π

Solve by substitution

cos (x) = - \frac{1}{2}, cos (x) = - 1

cos (x) = - \frac{1}{2}, 0 \leq x < 2 π : x = \frac{2 π}{3}, x = \frac{4 π}{3}

cos (x) = - 1, 0 \leq x < 2 π : x = π

Combine all the solutions

x = \frac{2 π}{3}, x = \frac{4 π}{3}, x = π

Popular Examples

tan(pi/2-x)+tan(x)-1=0

tan (\frac{π}{2} - x) + tan (x) - 1 = 0

cos (1000 t) = 1

3sin(θ/4)-3/2 =0,0<= θ<= 2pi

3 sin (\frac{θ}{4}) - \frac{3}{2} = 0, 0 \leq θ \leq 2 π

(1-tan^2(A))/(2tan(A))=cot(A)

\frac{1 - tan ^{2} ( A )}{2 tan ( A )} = cot (A)

cos(4θ)=cos(2θ),180<= θ<= 360

cos (4 θ) = cos (2 θ), 18 0^{\circ} \leq θ \leq 36 0^{\circ}

Frequently Asked Questions (FAQ)

What is the general solution for 2cos^2(x)+3cos(x)+1=0,0<= x<2pi ?
The general solution for 2cos^2(x)+3cos(x)+1=0,0<= x<2pi is x=(2pi)/3 ,x=(4pi)/3 ,x=pi