{
"query": {
"display": "$$-2\\cot\\left(θ\\right)=\\cot^{2}\\left(θ\\right)+1$$",
"symbolab_question": "EQUATION#-2\\cot(θ)=\\cot^{2}(θ)+1"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "θ=\\frac{3π}{4}+πn",
"degrees": "θ=135^{\\circ }+180^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$-2\\cot\\left(θ\\right)=\\cot^{2}\\left(θ\\right)+1{\\quad:\\quad}θ=\\frac{3π}{4}+πn$$",
"input": "-2\\cot\\left(θ\\right)=\\cot^{2}\\left(θ\\right)+1",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "-2\\cot\\left(θ\\right)=\\cot^{2}\\left(θ\\right)+1",
"result": "\\cot\\left(θ\\right)=-1",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cot\\left(θ\\right)=u$$",
"result": "-2u=u^{2}+1"
},
{
"type": "interim",
"title": "$$-2u=u^{2}+1{\\quad:\\quad}u=-1$$",
"input": "-2u=u^{2}+1",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "u^{2}+1=-2u"
},
{
"type": "interim",
"title": "Move $$2u\\:$$to the left side",
"input": "u^{2}+1=-2u",
"result": "u^{2}+1+2u=0",
"steps": [
{
"type": "step",
"primary": "Add $$2u$$ to both sides",
"result": "u^{2}+1+2u=-2u+2u"
},
{
"type": "step",
"primary": "Simplify",
"result": "u^{2}+1+2u=0"
}
],
"meta": {
"interimType": "Move to the Left Title 1Eq",
"gptData": "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"
}
},
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c=0$$",
"result": "u^{2}+2u+1=0"
},
{
"type": "interim",
"title": "Solve with the quadratic formula",
"input": "u^{2}+2u+1=0",
"result": "{u}_{1,\\:2}=\\frac{-2\\pm\\:\\sqrt{2^{2}-4\\cdot\\:1\\cdot\\:1}}{2\\cdot\\:1}",
"steps": [
{
"type": "definition",
"title": "Quadratic Equation Formula:",
"text": "For a quadratic equation of the form $$ax^2+bx+c=0$$ the solutions are <br/>$${\\quad}x_{1,\\:2}=\\frac{-b\\pm\\sqrt{b^2-4ac}}{2a}$$"
},
{
"type": "step",
"primary": "For $${\\quad}a=1,\\:b=2,\\:c=1$$",
"result": "{u}_{1,\\:2}=\\frac{-2\\pm\\:\\sqrt{2^{2}-4\\cdot\\:1\\cdot\\:1}}{2\\cdot\\:1}"
}
],
"meta": {
"interimType": "Solving The Quadratic Equation With Quadratic Formula Definition 0Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "$$2^{2}-4\\cdot\\:1\\cdot\\:1=0$$",
"input": "2^{2}-4\\cdot\\:1\\cdot\\:1",
"result": "{u}_{1,\\:2}=\\frac{-2\\pm\\:\\sqrt{0}}{2\\cdot\\:1}",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$4\\cdot\\:1\\cdot\\:1=4$$",
"result": "=2^{2}-4"
},
{
"type": "step",
"primary": "$$2^{2}=4$$",
"result": "=4-4"
},
{
"type": "step",
"primary": "Subtract the numbers: $$4-4=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7GEEX0EiNBYzwhkunUPgFxYcFPqa2dwwYBvRbhQUK9o4DnzlbPZjyKgy1eUCFsLd5uA0vbJw0XRhSBCaIjQqkFmVBHPdZOPO8WPbmsZqQtxm6v4V6Vpg/OWLsuIqa/9fQsIjaxJ4DvjTb2fbKjbvtlQ=="
}
},
{
"type": "step",
"result": "u=\\frac{-2}{2\\cdot\\:1}"
},
{
"type": "interim",
"title": "$$\\frac{-2}{2\\cdot\\:1}=-1$$",
"input": "\\frac{-2}{2\\cdot\\:1}",
"result": "u=-1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:1=2$$",
"result": "=\\frac{-2}{2}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{2}{2}"
},
{
"type": "step",
"primary": "Apply rule $$\\frac{a}{a}=1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7pQ0w2CFUmP3V08m8YszlLWgelhrK8M2TY4B4ebvtusYJQJZuTAY5js+oqjdT8kslMsz7gcINLRJHih26h/L+6fTmpwXN29XlGx6TKevDbs/ZlQvGb17FQnE0KcvUlNOsJLd1ohke2Wgml78++2zI0g=="
}
},
{
"type": "step",
"primary": "The solution to the quadratic equation is:",
"result": "u=-1"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cot\\left(θ\\right)$$",
"result": "\\cot\\left(θ\\right)=-1"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cot\\left(θ\\right)=-1{\\quad:\\quad}θ=\\frac{3π}{4}+πn$$",
"input": "\\cot\\left(θ\\right)=-1",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cot\\left(θ\\right)=-1$$",
"result": "θ=\\frac{3π}{4}+πn",
"steps": [
{
"type": "step",
"primary": "$$\\cot\\left(x\\right)$$ periodicity table with $$πn$$ cycle:<br/>$$\\begin{array}{|c|c|}\\hline x&\\cot(x)\\\\\\hline 0&\\mp\\infty\\\\\\hline \\frac{π}{6}&\\sqrt{3}\\\\\\hline \\frac{π}{4}&1\\\\\\hline \\frac{π}{3}&\\frac{\\sqrt{3}}{3}\\\\\\hline \\frac{π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{\\sqrt{3}}{3}\\\\\\hline \\frac{3π}{4}&-1\\\\\\hline \\frac{5π}{6}&-\\sqrt{3}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "θ=\\frac{3π}{4}+πn"
}
],
"meta": {
"interimType": "Trig General Solutions cot 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "θ=\\frac{3π}{4}+πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "θ",
"plotRequest": "-2\\cot(θ)-\\cot^{2}(θ)-1"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Switch sides
Move to the left side
Add to both sides
Simplify
Write in the standard form
Solve with the quadratic formula
Quadratic Equation Formula:
For
Multiply the numbers:
Subtract the numbers:
Multiply the numbers:
Apply the fraction rule:
Apply rule
The solution to the quadratic equation is:
Substitute back
General solutions for
periodicity table with cycle:
Combine all the solutions
Graph
Popular Examples
[sin(4x)cos(x)-cos(4x)sin(x)]^2=1cos(θ)=(202)/(sqrt(331)*2\sqrt{33)}5sin(θ)+12cos(θ)=132-2cos^2(x)+3cos(x)=0cot(x)= 5/12 ,pi<x<(3pi)/2
Frequently Asked Questions (FAQ)
What is the general solution for -2cot(θ)=cot^2(θ)+1 ?
The general solution for -2cot(θ)=cot^2(θ)+1 is θ=(3pi)/4+pin