What is the general solution for cos(2pix)*2pi+2pi=0 ?

The general solution for cos(2pix)*2pi+2pi=0 is x= 1/2+n

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cos(2pix)*2pi+2pi=0

cos (2 π x) \cdot 2 π + 2 π = 0

x = \frac{1}{2} + n

Solution steps

cos (2 π x) \cdot 2 π + 2 π = 0

Move

2 π

to the right side

cos (2 π x) \cdot 2 π = - 2 π

Divide both sides by

2 π

cos (2 π x) = - 1

General solutions for

cos (2 π x) = - 1

2 π x = π + 2 πn

Solve

2 π x = π + 2 πn : x = \frac{1}{2} + n

x = \frac{1}{2} + n

x, sin (y) = y cos (x)

4 sin (2 x) - 12 = 0, 0 \leq x \leq 2 π

1 \cdot 1 0^{6} = (400 \cdot cos (θ) + 700)^{2} + (400 \cdot sin (θ))^{2}

sin (x) - 0.5 \cdot cos (x) = 0.768

\frac{( 176 ) ^{2}}{300 \cdot 32.2} = tan (θ + 30.963 7^{\circ})

What is the general solution for cos(2pix)*2pi+2pi=0 ?
The general solution for cos(2pix)*2pi+2pi=0 is x= 1/2+n