What is the general solution for 0=1+4sin(θ) ?

The general solution for 0=1+4sin(θ) is θ=-0.25268…+2pin,θ=pi+0.25268…+2pin

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0=1+4sin(θ)

0 = 1 + 4 sin (θ)

θ = - 0.25268 \dots + 2 πn, θ = π + 0.25268 \dots + 2 πn

Solution steps

0 = 1 + 4 sin (θ)

Switch sides

1 + 4 sin (θ) = 0

Move

1

to the right side

4 sin (θ) = - 1

Divide both sides by

4

sin (θ) = - \frac{1}{4}

Apply trig inverse properties

θ = arcsin (- \frac{1}{4}) + 2 πn, θ = π + arcsin (\frac{1}{4}) + 2 πn

Show solutions in decimal form

θ = - 0.25268 \dots + 2 πn, θ = π + 0.25268 \dots + 2 πn

x, u = cos (x^{2} y)

6 sin^{2} (x) - sin (x) cos (x) - 2 cos^{2} (x) = 0

tan (θ) = \frac{20 ( 9.8 )}{25}

t, 0 = 8 sin (\frac{π t}{12}) + 32

sec^{2} (x) = \frac{1}{sin ^{2} ( x )}

What is the general solution for 0=1+4sin(θ) ?
The general solution for 0=1+4sin(θ) is θ=-0.25268…+2pin,θ=pi+0.25268…+2pin