What is the general solution for tan^3(x)=tan^2(x),0<= x<= 2pi ?

The general solution for tan^3(x)=tan^2(x),0<= x<= 2pi is x=0,x=pi,x=2pi,x= pi/4 ,x=(5pi)/4

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tan^3(x)=tan^2(x),0<= x<= 2pi

tan^{3} (x) = tan^{2} (x), 0 \leq x \leq 2 π

x = 0, x = π, x = 2 π, x = \frac{π}{4}, x = \frac{5 π}{4}

Solution steps

tan^{3} (x) = tan^{2} (x), 0 \leq x \leq 2 π

Solve by substitution

tan (x) = 0, tan (x) = 1

tan (x) = 0, 0 \leq x \leq 2 π : x = 0, x = π, x = 2 π

tan (x) = 1, 0 \leq x \leq 2 π : x = \frac{π}{4}, x = \frac{5 π}{4}

Combine all the solutions

x = 0, x = π, x = 2 π, x = \frac{π}{4}, x = \frac{5 π}{4}

11.75 = 5 sin (\frac{π t}{6} - \frac{7 π}{6}) + 8

0 = - 2 sin (x) - 2 cos (2 x)

- sin (c) + cos (c) + 1 = 0

cot (a) = \frac{7}{51}

sin (x) = \frac{39}{44}

What is the general solution for tan^3(x)=tan^2(x),0<= x<= 2pi ?
The general solution for tan^3(x)=tan^2(x),0<= x<= 2pi is x=0,x=pi,x=2pi,x= pi/4 ,x=(5pi)/4