What is the general solution for sin(x)=-2cos(x) ?

The general solution for sin(x)=-2cos(x) is x=-1.10714…+pin

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sin(x)=-2cos(x)

sin (x) = - 2 cos (x)

x = - 1.10714 \dots + πn

Solution steps

sin (x) = - 2 cos (x)

Rewrite using trig identities

tan (x) = - 2

Apply trig inverse properties

x = arctan (- 2) + πn

Show solutions in decimal form

x = - 1.10714 \dots + πn

3 sin^{2} (x) - 4 cos (x) + 1 = 0

sin (x) - cos (2 x) - 1 = 0

sin^{2} (x) = 3

x, c^{2} = a^{2} + b^{2} - 2 ab \cdot cos (x)

sin (- \frac{π}{8} c) = - \frac{14}{14}

What is the general solution for sin(x)=-2cos(x) ?
The general solution for sin(x)=-2cos(x) is x=-1.10714…+pin