What is the general solution for ((2sin(x))(sin(x)))/(sin(x))+1=3 ?

The general solution for ((2sin(x))(sin(x)))/(sin(x))+1=3 is x= pi/2+2pin

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((2sin(x))(sin(x)))/(sin(x))+1=3

\frac{( 2 sin ( x ) ) ( sin ( x ) )}{sin ( x )} + 1 = 3

x = \frac{π}{2} + 2 πn

Solution steps

\frac{( 2 sin ( x ) ) ( sin ( x ) )}{sin ( x )} + 1 = 3

Simplify

\frac{2 sin ( x ) sin ( x )}{sin ( x )} + 1 : 2 sin (x) + 1

2 sin (x) + 1 = 3

Move

1

to the right side

2 sin (x) = 2

Divide both sides by

2

sin (x) = 1

General solutions for

sin (x) = 1

x = \frac{π}{2} + 2 πn

tan (2 θ) = - \frac{2}{5}

cos (2 x) - 3 cos (x) = - 2

3 cos (x) - 3 sin (x) = 0

cos^{2} (3 x) = cos (9 x^{2})

2 cos (θ) - 2 = 0

What is the general solution for ((2sin(x))(sin(x)))/(sin(x))+1=3 ?
The general solution for ((2sin(x))(sin(x)))/(sin(x))+1=3 is x= pi/2+2pin