What is the general solution for tan(θ)= 5/2 ,0<θ< pi/2 ,sin(θ/2) ?

The general solution for tan(θ)= 5/2 ,0<θ< pi/2 ,sin(θ/2) is θ=1.19028…

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tan(θ)= 5/2 ,0<θ< pi/2 ,sin(θ/2)

tan (θ) = \frac{5}{2}, 0 < θ < \frac{π}{2}, sin (\frac{θ}{2})

θ = 1.19028 \dots

Solution steps

tan (θ) = \frac{5}{2}, 0 < θ < \frac{π}{2}, sin (\frac{θ}{2})

Apply trig inverse properties

θ = arctan (\frac{5}{2}) + πn

Solutions for the range

0 < θ < \frac{π}{2}

θ = arctan (\frac{5}{2})

Show solutions in decimal form

θ = 1.19028 \dots

3 = 20.39 sin (θ) cos (θ)

sin^{4} (x) = \frac{1}{16}

sec (y) = \frac{4}{5}

(tan^{2} (x) - 1) (csc (x) + 1) = 0

12 sin^{2} (θ) - 3 = 0, 0 \leq θ \leq 2 π

What is the general solution for tan(θ)= 5/2 ,0<θ< pi/2 ,sin(θ/2) ?
The general solution for tan(θ)= 5/2 ,0<θ< pi/2 ,sin(θ/2) is θ=1.19028…