What is the value of cos((27pi)/2) ?

The value of cos((27pi)/2) is 0

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cos((27pi)/2)

cos (\frac{27 π}{2})

0

Solution steps

cos (\frac{27 π}{2})

cos (\frac{27 π}{2}) = cos (\frac{3 π}{2})

= cos (\frac{3 π}{2})

Rewrite using trig identities:

cos (π) cos (\frac{π}{2}) - sin (π) sin (\frac{π}{2})

= cos (π) cos (\frac{π}{2}) - sin (π) sin (\frac{π}{2})

Use the following trivial identity:

cos (π) = (- 1)

Use the following trivial identity:

cos (\frac{π}{2}) = 0

Use the following trivial identity:

sin (π) = 0

Use the following trivial identity:

sin (\frac{π}{2}) = 1

= (- 1) \cdot 0 - 0 \cdot 1

Simplify

= 0

arccos (\frac{4}{5 5})

cos (4 5^{\circ}) - csc (3 0^{\circ})

cos (\frac{3 π}{4}) + i sin (\frac{3 π}{4})

tan (- 0.1)

sin (arcsin (\frac{9}{41}) - arccos (- \frac{4}{5}))