What is the general solution for 2-2cosh(t-2)=0 ?

The general solution for 2-2cosh(t-2)=0 is t=2

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2-2cosh(t-2)=0

2 - 2 cosh (t - 2) = 0

t = 2

Solution steps

2 - 2 cosh (t - 2) = 0

Rewrite using trig identities

2 - 2 \cdot \frac{e ^{t - 2} + e ^{- (t - 2)}}{2} = 0

2 - 2 \cdot \frac{e ^{t - 2} + e ^{- (t - 2)}}{2} = 0 : t = 2

t = 2

cos (x) = \frac{1}{37}

\frac{sin ( 2 x )}{cos ( x )} = 4 + sin (2 x) \cdot tan (x)

sin (x) = 0.2174

x, arccot (x^{2}) y = arccot (x^{2})

\frac{50}{33} = \frac{sin ( x )}{sin ( 12 0 ^{\circ} - x )}

What is the general solution for 2-2cosh(t-2)=0 ?
The general solution for 2-2cosh(t-2)=0 is t=2