What is the general solution for cos(θ)=-0.47 ?

The general solution for cos(θ)=-0.47 is θ=2.06008…+2pin,θ=-2.06008…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)=-0.47

cos (θ) = - 0.47

θ = 2.06008 \dots + 2 πn, θ = - 2.06008 \dots + 2 πn

Solution steps

cos (θ) = - 0.47

Apply trig inverse properties

θ = arccos (- 0.47) + 2 πn, θ = - arccos (- 0.47) + 2 πn

Show solutions in decimal form

θ = 2.06008 \dots + 2 πn, θ = - 2.06008 \dots + 2 πn

1 + tan^{2} (x) cos (x) = sec (x)

sec (θ) = \frac{6}{2}

sin^{2} (x) + cos^{2} (x) = sin (x) csc^{2} (x)

1.5 2 = 3 cos (x)

\frac{sin ( 5 9 ^{\circ} )}{8} = \frac{sin ( x )}{9.25}

What is the general solution for cos(θ)=-0.47 ?
The general solution for cos(θ)=-0.47 is θ=2.06008…+2pin,θ=-2.06008…+2pin