What is the general solution for cos(θ)=-0.19 ?

The general solution for cos(θ)=-0.19 is θ=1.76195…+2pin,θ=-1.76195…+2pin

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cos(θ)=-0.19

cos (θ) = - 0.19

θ = 1.76195 \dots + 2 πn, θ = - 1.76195 \dots + 2 πn

Solution steps

cos (θ) = - 0.19

Apply trig inverse properties

θ = arccos (- 0.19) + 2 πn, θ = - arccos (- 0.19) + 2 πn

Show solutions in decimal form

θ = 1.76195 \dots + 2 πn, θ = - 1.76195 \dots + 2 πn

9 cos^{2} (x) = 2

tan (θ) = \frac{6}{14}

tan (θ) = \frac{6}{15}

tan (x) = \frac{10}{3}

csc^{2} (x) - csc (x) - 2 = 0, - π \leq x \leq π

What is the general solution for cos(θ)=-0.19 ?
The general solution for cos(θ)=-0.19 is θ=1.76195…+2pin,θ=-1.76195…+2pin