What is the general solution for -1+sin(x)+2sin^2(x)=0 ?

The general solution for -1+sin(x)+2sin^2(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=(3pi)/2+2pin

Popular >

-1+sin(x)+2sin^2(x)=0

- 1 + sin (x) + 2 sin^{2} (x) = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

- 1 + sin (x) + 2 sin^{2} (x) = 0

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - 1

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{3 π}{2} + 2 πn

\frac{cos ( α - 3 0 ^{\circ} )}{1} = \frac{sin ( 6 0 ^{\circ} )}{3}

tan (x) tan (7 x) = 1, x

3 sec^{2} (x) + tan (x) - 6 = 0

2 sin (x) + cot (x) = csc (x)

8 cos^{2} (x) + 2 cos (x) - 3 = 0

What is the general solution for -1+sin(x)+2sin^2(x)=0 ?
The general solution for -1+sin(x)+2sin^2(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=(3pi)/2+2pin