What is the general solution for sin^2(θ)=3(cos(-θ)+1) ?

The general solution for sin^2(θ)=3(cos(-θ)+1) is θ=pi+2pin

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sin^2(θ)=3(cos(-θ)+1)

sin^{2} (θ) = 3 (cos (- θ) + 1)

θ = π + 2 πn

Solution steps

sin^{2} (θ) = 3 (cos (- θ) + 1)

Rewrite using trig identities

sin^{2} (θ) = 3 (1 + cos (θ))

Subtract

3 (1 + cos (θ))

from both sides

sin^{2} (θ) - 3 (1 + cos (θ)) = 0

Rewrite using trig identities

- 2 - cos^{2} (θ) - 3 cos (θ) = 0

Solve by substitution

cos (θ) = - 2, cos (θ) = - 1

cos (θ) = - 2 :

No Solution

cos (θ) = - 1 : θ = π + 2 πn

Combine all the solutions

θ = π + 2 πn

arctan (x \cdot 10000 π) = 12 6^{\circ}

sin^{2} (x) \cdot cos^{2} (x) = 1

5.8 = 11.8 sin (3.78 \cdot t)

- 1 + sin (x) + 2 sin^{2} (x) = 0

\frac{cos ( α - 3 0 ^{\circ} )}{1} = \frac{sin ( 6 0 ^{\circ} )}{3}

What is the general solution for sin^2(θ)=3(cos(-θ)+1) ?
The general solution for sin^2(θ)=3(cos(-θ)+1) is θ=pi+2pin