What is the general solution for sin(θ)=0.321 ?

The general solution for sin(θ)=0.321 is θ=0.32678…+2pin,θ=pi-0.32678…+2pin

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sin(θ)=0.321

sin (θ) = 0.321

θ = 0.32678 \dots + 2 πn, θ = π - 0.32678 \dots + 2 πn

Degrees

θ = 18.72341 \dots^{\circ} + 36 0^{\circ} n, θ = 161.27658 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = 0.321

Apply trig inverse properties

sin (θ) = 0.321

General solutions for

sin (θ) = 0.321

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (0.321) + 2 πn, θ = π - arcsin (0.321) + 2 πn

θ = arcsin (0.321) + 2 πn, θ = π - arcsin (0.321) + 2 πn

Show solutions in decimal form

θ = 0.32678 \dots + 2 πn, θ = π - 0.32678 \dots + 2 πn

What is the general solution for sin(θ)=0.321 ?
The general solution for sin(θ)=0.321 is θ=0.32678…+2pin,θ=pi-0.32678…+2pin