What is the general solution for solvefor x,z=arcsin(x+y) ?

The general solution for solvefor x,z=arcsin(x+y) is x=sin(z)-y

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solvefor x,z=arcsin(x+y)

solve for

x, z = arcsin (x + y)

x = sin (z) - y

Solution steps

z = arcsin (x + y)

Switch sides

arcsin (x + y) = z

Apply trig inverse properties

arcsin (x + y) = z

arcsin (x) = a \Rightarrow x = sin (a)

x + y = sin (z)

x + y = sin (z)

Solve

x + y = sin (z) : x = sin (z) - y

x + y = sin (z)

Move

y

to the right side

x + y = sin (z)

Subtract

y

from both sides

x + y - y = sin (z) - y

Simplify

x = sin (z) - y

x = sin (z) - y

x = sin (z) - y

150 cos (x - 8) = 0

8 sin^{2} (x) - 6 sin (x) + 1 = 0

sin (5 x) - cos (3 0^{\circ}) = 0

2 cos^{2} (t) + 2 cos (2 t) = 0

tan^{3} (θ) = tan (θ)

What is the general solution for solvefor x,z=arcsin(x+y) ?
The general solution for solvefor x,z=arcsin(x+y) is x=sin(z)-y