What is the general solution for cos(θ)=-(sqrt(53))/8 ?

The general solution for cos(θ)=-(sqrt(53))/8 is θ=2.71411…+2pin,θ=-2.71411…+2pin

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cos(θ)=-(sqrt(53))/8

cos (θ) = - \frac{53}{8}

θ = 2.71411 \dots + 2 πn, θ = - 2.71411 \dots + 2 πn

Degrees

θ = 155.50724 \dots^{\circ} + 36 0^{\circ} n, θ = - 155.50724 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - \frac{53}{8}

Apply trig inverse properties

cos (θ) = - \frac{53}{8}

General solutions for

cos (θ) = - \frac{53}{8}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{53}{8}) + 2 πn, θ = - arccos (- \frac{53}{8}) + 2 πn

θ = arccos (- \frac{53}{8}) + 2 πn, θ = - arccos (- \frac{53}{8}) + 2 πn

Show solutions in decimal form

θ = 2.71411 \dots + 2 πn, θ = - 2.71411 \dots + 2 πn

\frac{sin ( 15 0 ^{\circ} )}{500} = \frac{sin ( x )}{45}

sec (x) - tan (x) = 2

sin (\frac{2 π ( t + 101.75 )}{365}) = - 1

2 sin^{2} (θ) - 2 = cos^{2} (θ), 0 \leq θ \leq 2 π

cos (θ) = - \frac{7}{5}

What is the general solution for cos(θ)=-(sqrt(53))/8 ?
The general solution for cos(θ)=-(sqrt(53))/8 is θ=2.71411…+2pin,θ=-2.71411…+2pin