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Popular >

sec(θ)=15,tan(2θ)+125(cos(2θ)-1)

Solution

sec (θ) = 15, tan (2 θ) + 125 (cos (2 θ) - 1)

Solution

No Solution for θ \in R

Solution steps

sec (θ) = 15, tan (2 θ) + 125 (cos (2 θ) - 1)

Apply trig inverse properties

sec (θ) = 15

General solutions for

sec (θ) = 15

sec (x) = a \Rightarrow x = arcsec (a) + 2 πn, x = 2 π - arcsec (a) + 2 πn

θ = arcsec (15) + 2 πn, θ = 2 π - arcsec (15) + 2 πn

θ = arcsec (15) + 2 πn, θ = 2 π - arcsec (15) + 2 πn

Solutions for the range

tan (2 θ) + 125 (cos (2 θ) - 1)

No Solution for θ \in R

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Frequently Asked Questions (FAQ)

What is the general solution for sec(θ)=15,tan(2θ)+125(cos(2θ)-1) ?
The general solution for sec(θ)=15,tan(2θ)+125(cos(2θ)-1) is No Solution for θ\in\mathbb{R}