What is the general solution for -cos(74)=cos(θ) ?

The general solution for -cos(74)=cos(θ) is θ=1.85004…+360n,θ=-1.85004…+360n

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-cos(74)=cos(θ)

- cos (7 4^{\circ}) = cos (θ)

θ = 1.85004 \dots + 36 0^{\circ} n, θ = - 1.85004 \dots + 36 0^{\circ} n

Radians

θ = 1.85004 \dots + 2 πn, θ = - 1.85004 \dots + 2 πn

Solution steps

- cos (7 4^{\circ}) = cos (θ)

Switch sides

cos (θ) = - cos (7 4^{\circ})

Apply trig inverse properties

cos (θ) = - cos (7 4^{\circ})

General solutions for

cos (θ) = - cos (7 4^{\circ})

cos (x) = - a \Rightarrow x = arccos (- a) + 36 0^{\circ} n, x = - arccos (- a) + 36 0^{\circ} n

θ = arccos (- cos (7 4^{\circ})) + 36 0^{\circ} n, θ = - arccos (- cos (7 4^{\circ})) + 36 0^{\circ} n

θ = arccos (- cos (7 4^{\circ})) + 36 0^{\circ} n, θ = - arccos (- cos (7 4^{\circ})) + 36 0^{\circ} n

Show solutions in decimal form

θ = 1.85004 \dots + 36 0^{\circ} n, θ = - 1.85004 \dots + 36 0^{\circ} n

sin (x) = 50

58. 2^{2} = 25. 8^{2} + 33. 4^{2} - 2 (25.8 (33.4)) cos (a)

tan (θ) = - 3, 0 \leq θ \leq 2 π

4 cos (θ) - 1 = 2 sin (θ) tan (θ)

3 tan (θ) = tan (2 θ)

What is the general solution for -cos(74)=cos(θ) ?
The general solution for -cos(74)=cos(θ) is θ=1.85004…+360n,θ=-1.85004…+360n