What is the general solution for tan(θ)=-sqrt(3),0<= θ<= 2pi ?

The general solution for tan(θ)=-sqrt(3),0<= θ<= 2pi is θ=(2pi)/3 ,θ=(5pi)/3

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tan(θ)=-sqrt(3),0<= θ<= 2pi

tan (θ) = - 3, 0 \leq θ \leq 2 π

θ = \frac{2 π}{3}, θ = \frac{5 π}{3}

Degrees

θ = 12 0^{\circ}, θ = 30 0^{\circ}

Solution steps

tan (θ) = - 3, 0 \leq θ \leq 2 π

General solutions for

tan (θ) = - 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{2 π}{3} + πn

θ = \frac{2 π}{3} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{2 π}{3}, θ = \frac{5 π}{3}

4 cos (θ) - 1 = 2 sin (θ) tan (θ)

3 tan (θ) = tan (2 θ)

cos^{(2)} (x) - 3 sin^{(2)} (x) = 0

a, cos (a) cos (b) = 0.426

5 cos (x) - 4 = 0

What is the general solution for tan(θ)=-sqrt(3),0<= θ<= 2pi ?
The general solution for tan(θ)=-sqrt(3),0<= θ<= 2pi is θ=(2pi)/3 ,θ=(5pi)/3