What is the general solution for sin(θ)=(sqrt(2-\sqrt{3)})/(10) ?

The general solution for sin(θ)=(sqrt(2-\sqrt{3)})/(10) is θ=0.05178…+2pin,θ=pi-0.05178…+2pin

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sin(θ)=(sqrt(2-\sqrt{3)})/(10)

sin (θ) = \frac{2 - 3}{10}

θ = 0.05178 \dots + 2 πn, θ = π - 0.05178 \dots + 2 πn

Degrees

θ = 2.96717 \dots^{\circ} + 36 0^{\circ} n, θ = 177.03282 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{2 - 3}{10}

Apply trig inverse properties

sin (θ) = \frac{2 - 3}{10}

General solutions for

sin (θ) = \frac{2 - 3}{10}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{2 - 3}{10}) + 2 πn, θ = π - arcsin (\frac{2 - 3}{10}) + 2 πn

θ = arcsin (\frac{2 - 3}{10}) + 2 πn, θ = π - arcsin (\frac{2 - 3}{10}) + 2 πn

Show solutions in decimal form

θ = 0.05178 \dots + 2 πn, θ = π - 0.05178 \dots + 2 πn

sin (x) = 0.844

2 cos (x) = - cos (x)

tan (x) = - 10

cos (\frac{π}{x}) = \frac{3}{3}

y, arctan (\frac{y}{x}) = ln (x)

What is the general solution for sin(θ)=(sqrt(2-\sqrt{3)})/(10) ?
The general solution for sin(θ)=(sqrt(2-\sqrt{3)})/(10) is θ=0.05178…+2pin,θ=pi-0.05178…+2pin