ko

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

인기 있는 삼각법 >

cos(pi/x)=(sqrt(3))/3

해법

cos (\frac{π}{x}) = \frac{3}{3}

해법

x = \frac{π}{0.95531 \dots + 2 πn}, x = \frac{π}{2 π - 0.95531 \dots + 2 πn}

+1

도

x = 0^{\circ} + 24.86702 \dots^{\circ} n, x = 0^{\circ} + 15.50246 \dots^{\circ} n

솔루션 단계

cos (\frac{π}{x}) = \frac{3}{3}

트리거 역속성 적용

cos (\frac{π}{x}) = \frac{3}{3}

일반 솔루션

cos (\frac{π}{x}) = \frac{3}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn, \frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn, \frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn

해결 :

x = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn

양쪽을 곱한 값

x

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn

양쪽을 곱한 값

x

\frac{π}{x} x = arccos (\frac{3}{3}) x + 2 πn x

단순화

π = arccos (\frac{3}{3}) x + 2 πn x

π = arccos (\frac{3}{3}) x + 2 πn x

측면 전환

arccos (\frac{3}{3}) x + 2 πn x = π

arccos (\frac{3}{3}) x + 2 πn x

간소화하다 :

arccos (\frac{1}{3}) x + 2 πn x

arccos (\frac{3}{3}) x + 2 πn x

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

급진적인 규칙 적용:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

숫자를 빼세요:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

급진적인 규칙 적용:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= arccos (\frac{1}{3}) x + 2 πn x

arccos (\frac{1}{3}) x + 2 πn x = π

arccos (\frac{3}{3}) x + 2 πn x = π

arccos (\frac{3}{3}) x + 2 πn x

요인:

x (arccos (\frac{1}{3}) + 2 πn)

arccos (\frac{3}{3}) x + 2 πn x

공통 용어를 추출하다

x

= x (arccos (\frac{3}{3}) + 2 πn)

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

급진적인 규칙 적용:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

숫자를 빼세요:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

급진적인 규칙 적용:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= x (2 πn + arccos (\frac{1}{3}))

x (arccos (\frac{1}{3}) + 2 πn) = π

양쪽을 다음으로 나눕니다

arccos (\frac{1}{3}) + 2 πn; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

x (arccos (\frac{1}{3}) + 2 πn) = π

양쪽을 다음으로 나눕니다

arccos (\frac{1}{3}) + 2 πn; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

단순화

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn}

간소화하다 :

x

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn}

x (arccos (\frac{1}{3}) + 2 πn) = x (arccos (\frac{3}{3}) + 2 πn)

x (arccos (\frac{1}{3}) + 2 πn)

= x (2 πn + arccos (\frac{3}{3}))

= \frac{x ( 2 πn + arccos ( \frac{3}{3} ) )}{arccos ( \frac{1}{3} ) + 2 πn}

arccos (\frac{1}{3}) + 2 πn = arccos (\frac{3}{3}) + 2 πn

arccos (\frac{1}{3}) + 2 πn

= arccos (\frac{3}{3}) + 2 πn

= \frac{x ( 2 πn + arccos ( \frac{3}{3} ) )}{arccos ( \frac{3}{3} ) + 2 πn}

공통 요인 취소:

arccos (\frac{3}{3}) + 2 πn

= x

\frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

간소화하다 :

\frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

\frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

arccos (\frac{1}{3}) + 2 πn = arccos (\frac{3}{3}) + 2 πn

arccos (\frac{1}{3}) + 2 πn

= arccos (\frac{3}{3}) + 2 πn

= \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

x = \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

\frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

간소화하다 :

\frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

\frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

급진적인 규칙 적용:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

숫자를 빼세요:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

급진적인 규칙 적용:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

x = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

\frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

해결 :

x = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

\frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

양쪽을 곱한 값

x

\frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

양쪽을 곱한 값

x

\frac{π}{x} x = 2 π x - arccos (\frac{3}{3}) x + 2 πn x

단순화

π = 2 π x - arccos (\frac{3}{3}) x + 2 πn x

π = 2 π x - arccos (\frac{3}{3}) x + 2 πn x

측면 전환

2 π x - arccos (\frac{3}{3}) x + 2 πn x = π

2 π x - arccos (\frac{3}{3}) x + 2 πn x

간소화하다 :

2 π x - arccos (\frac{1}{3}) x + 2 πn x

2 π x - arccos (\frac{3}{3}) x + 2 πn x

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

급진적인 규칙 적용:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

숫자를 빼세요:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

급진적인 규칙 적용:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= 2 π x - arccos (\frac{1}{3}) x + 2 πn x

2 π x - arccos (\frac{1}{3}) x + 2 πn x = π

2 π x - arccos (\frac{3}{3}) x + 2 πn x = π

2 π x - arccos (\frac{3}{3}) x + 2 πn x

요인:

x (2 π - arccos (\frac{1}{3}) + 2 πn)

2 π x - arccos (\frac{3}{3}) x + 2 πn x

공통 용어를 추출하다

x

= x (2 π - arccos (\frac{3}{3}) + 2 πn)

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

급진적인 규칙 적용:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

숫자를 빼세요:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

급진적인 규칙 적용:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= x (2 π + 2 πn - arccos (\frac{1}{3}))

x (2 π - arccos (\frac{1}{3}) + 2 πn) = π

양쪽을 다음으로 나눕니다

2 π - arccos (\frac{1}{3}) + 2 πn; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x (2 π - arccos (\frac{1}{3}) + 2 πn) = π

양쪽을 다음으로 나눕니다

2 π - arccos (\frac{1}{3}) + 2 πn; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

단순화

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

간소화하다 :

x

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

x (2 π - arccos (\frac{1}{3}) + 2 πn) = x (2 π - arccos (\frac{3}{3}) + 2 πn)

x (2 π - arccos (\frac{1}{3}) + 2 πn)

= x (2 π + 2 πn - arccos (\frac{3}{3}))

= \frac{x ( 2 π + 2 πn - arccos ( \frac{3}{3} ) )}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

2 π - arccos (\frac{1}{3}) + 2 πn = 2 π - arccos (\frac{3}{3}) + 2 πn

2 π - arccos (\frac{1}{3}) + 2 πn

= 2 π - arccos (\frac{3}{3}) + 2 πn

= \frac{x ( 2 π + 2 πn - arccos ( \frac{3}{3} ) )}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

공통 요인 취소:

2 π - arccos (\frac{3}{3}) + 2 πn

= x

\frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

간소화하다 :

\frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

\frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

2 π - arccos (\frac{1}{3}) + 2 πn = 2 π - arccos (\frac{3}{3}) + 2 πn

2 π - arccos (\frac{1}{3}) + 2 πn

= 2 π - arccos (\frac{3}{3}) + 2 πn

= \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

x = \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

\frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

간소화하다 :

\frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

\frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

급진적인 규칙 적용:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

숫자를 빼세요:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

급진적인 규칙 적용:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

x = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}, x = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

해를 10진수 형식으로 표시

x = \frac{π}{0.95531 \dots + 2 πn}, x = \frac{π}{2 π - 0.95531 \dots + 2 πn}

그래프

인기 있는 예

solvefor y,arctan(y/x)=ln(x)

58.2^2=25.8^2+33.4^2-2(25.8(33.4))cos(a)

4cos(θ)-1=2sin(θ)tan(θ)

3tan(θ)=tan(2θ)