What is the general solution for cos(θ)= 20/27 ?

The general solution for cos(θ)= 20/27 is θ=0.73662…+2pin,θ=2pi-0.73662…+2pin

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cos(θ)= 20/27

cos (θ) = \frac{20}{27}

θ = 0.73662 \dots + 2 πn, θ = 2 π - 0.73662 \dots + 2 πn

Degrees

θ = 42.20544 \dots^{\circ} + 36 0^{\circ} n, θ = 317.79455 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{20}{27}

Apply trig inverse properties

cos (θ) = \frac{20}{27}

General solutions for

cos (θ) = \frac{20}{27}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{20}{27}) + 2 πn, θ = 2 π - arccos (\frac{20}{27}) + 2 πn

θ = arccos (\frac{20}{27}) + 2 πn, θ = 2 π - arccos (\frac{20}{27}) + 2 πn

Show solutions in decimal form

θ = 0.73662 \dots + 2 πn, θ = 2 π - 0.73662 \dots + 2 πn

32 cos (x) + 2 = - 1

\frac{1}{sin ( x ) \cdot cos ( x ) + cos ( x )} = \frac{1}{cos ( x )}

4 = tan^{2} (4 5^{\circ} + \frac{x}{2})

2 sin (5 x) - 1 = 0

cos (x) = \frac{2.3}{2.8}

What is the general solution for cos(θ)= 20/27 ?
The general solution for cos(θ)= 20/27 is θ=0.73662…+2pin,θ=2pi-0.73662…+2pin