What is the general solution for 1/(sin(x)*cos(x)+cos(x))= 1/(cos(x)) ?

The general solution for 1/(sin(x)*cos(x)+cos(x))= 1/(cos(x)) is x=2pin,x=pi+2pin

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1/(sin(x)*cos(x)+cos(x))= 1/(cos(x))

\frac{1}{sin ( x ) \cdot cos ( x ) + cos ( x )} = \frac{1}{cos ( x )}

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

\frac{1}{sin ( x ) cos ( x ) + cos ( x )} = \frac{1}{cos ( x )}

Subtract

\frac{1}{cos ( x )}

from both sides

- \frac{sin ( x )}{cos ( x ) ( sin ( x ) + 1 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- (sin (x)) = 0

Divide both sides by

- 1

- (sin (x)) = 0

Divide both sides by

- 1

\frac{- sin ( x )}{- 1} = \frac{0}{- 1}

Simplify

sin (x) = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

4 = tan^{2} (4 5^{\circ} + \frac{x}{2})

2 sin (5 x) - 1 = 0

cos (x) = \frac{2.3}{2.8}

3000 = 5000 [cos (\frac{π}{45} (t - 6))]

2 + cos (θ) = 5 cos (θ)

What is the general solution for 1/(sin(x)*cos(x)+cos(x))= 1/(cos(x)) ?
The general solution for 1/(sin(x)*cos(x)+cos(x))= 1/(cos(x)) is x=2pin,x=pi+2pin