What is the general solution for cos(a)=-3/5 ,sin(a)>0 ?

The general solution for cos(a)=-3/5 ,sin(a)>0 is No Solution for a\in\mathbb{R}

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cos(a)=-3/5 ,sin(a)>0

cos (a) = - \frac{3}{5}, sin (a) > 0

No Solution for a \in R

Solution steps

cos (a) = - \frac{3}{5}, sin (a) > 0

Apply trig inverse properties

cos (a) = - \frac{3}{5}

General solutions for

cos (a) = - \frac{3}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

a = arccos (- \frac{3}{5}) + 2 πn, a = - arccos (- \frac{3}{5}) + 2 πn

a = arccos (- \frac{3}{5}) + 2 πn, a = - arccos (- \frac{3}{5}) + 2 πn

Solutions for the range

sin (a) > 0

No Solution for a \in R

cot (x) - cot (33.4 7^{\circ}) = \frac{1485}{2460}

3 + \frac{1}{5} cos (\frac{θ}{3} + \frac{7 π}{4}) = 3

sin (θ) = - \frac{13}{7}

- 2 sin (x) = - 2

sin (π - x) = cos (\frac{3 π}{2} - x) + cos (π)

What is the general solution for cos(a)=-3/5 ,sin(a)>0 ?
The general solution for cos(a)=-3/5 ,sin(a)>0 is No Solution for a\in\mathbb{R}