What is the general solution for cos(t)=-0,5 ?

The general solution for cos(t)=-0,5 is No Solution for t\in\mathbb{R}

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cos(t)=-0,5

cos (t) = - 0, 5

No Solution for t \in R

Solution steps

cos (t) = - 0, 5

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Solutions for the range

5

No Solution for t \in R

sinh (x) = sinh (- x)

\frac{π}{4} = arctan (t)

sin (2 x) sin (x) cos (x) = 0

sin (4 x) - cos (4 x) = sin (2 x) - cos (2 x)

2 \cdot sin^{2} (x) - 1 = 0

What is the general solution for cos(t)=-0,5 ?
The general solution for cos(t)=-0,5 is No Solution for t\in\mathbb{R}