What is the general solution for (sqrt(2))/2 cos(t)=0 ?

The general solution for (sqrt(2))/2 cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin

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(sqrt(2))/2 cos(t)=0

\frac{2}{2} cos (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

\frac{2}{2} cos (t) = 0

Multiply both sides by

2

\frac{2}{2} cos (t) = 0

Multiply both sides by

2

2 \cdot \frac{2}{2} cos (t) = 0 \cdot 2

Simplify

2 cos (t) = 0

2 cos (t) = 0

Divide both sides by

2

2 cos (t) = 0

Divide both sides by

2

\frac{2 cos ( t )}{2} = \frac{0}{2}

Simplify

cos (t) = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

3 sin (x) - cos (x) = 2

5 - 20 cos^{2} (t) = 0

10 tan (B) + 12 = tan (B) + 6

cos (θ) = - \frac{5}{8}

\frac{368.02}{sin ( 6 6 ^{\circ} - x )} = \frac{290}{sin ( 3 8 ^{\circ} )}

What is the general solution for (sqrt(2))/2 cos(t)=0 ?
The general solution for (sqrt(2))/2 cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin