What is the general solution for cos(θ)=-sqrt(2/5),tan(2θ) ?

The general solution for cos(θ)=-sqrt(2/5),tan(2θ) is No Solution for θ\in\mathbb{R}

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cos(θ)=-sqrt(2/5),tan(2θ)

cos (θ) = - \frac{2}{5}, tan (2 θ)

No Solution for θ \in R

Solution steps

cos (θ) = - \frac{2}{5}, tan (2 θ)

Apply trig inverse properties

cos (θ) = - \frac{2}{5}

General solutions for

cos (θ) = - \frac{2}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{2}{5}) + 2 πn, θ = - arccos (- \frac{2}{5}) + 2 πn

θ = arccos (- \frac{2}{5}) + 2 πn, θ = - arccos (- \frac{2}{5}) + 2 πn

Solutions for the range

tan (2 θ)

No Solution for θ \in R

sin (x + \frac{π}{6}) = \frac{2}{2}

\frac{1}{2} = cos (x)

2 sin (4 x) = sin (2 x)

csc (x) sec (x) = 22

u, x = sinh (u)

What is the general solution for cos(θ)=-sqrt(2/5),tan(2θ) ?
The general solution for cos(θ)=-sqrt(2/5),tan(2θ) is No Solution for θ\in\mathbb{R}