What is the general solution for cos(β)= 2/7 ?

The general solution for cos(β)= 2/7 is β=1.28104…+2pin,β=2pi-1.28104…+2pin

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cos(β)= 2/7

cos (β) = \frac{2}{7}

β = 1.28104 \dots + 2 πn, β = 2 π - 1.28104 \dots + 2 πn

Degrees

β = 73.39845 \dots^{\circ} + 36 0^{\circ} n, β = 286.60154 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (β) = \frac{2}{7}

Apply trig inverse properties

cos (β) = \frac{2}{7}

General solutions for

cos (β) = \frac{2}{7}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

β = arccos (\frac{2}{7}) + 2 πn, β = 2 π - arccos (\frac{2}{7}) + 2 πn

β = arccos (\frac{2}{7}) + 2 πn, β = 2 π - arccos (\frac{2}{7}) + 2 πn

Show solutions in decimal form

β = 1.28104 \dots + 2 πn, β = 2 π - 1.28104 \dots + 2 πn

tan (x) = \frac{930}{1793}

sin (x) + cos (x) = 0.2

sin (x) cos (x) = - \frac{2}{4}

sin (a) = 0.3

sin (x) = \frac{5}{13}, tan (x), \frac{π}{2} \leq x \leq π

What is the general solution for cos(β)= 2/7 ?
The general solution for cos(β)= 2/7 is β=1.28104…+2pin,β=2pi-1.28104…+2pin