What is the general solution for sec(θ)=-7/(sqrt(13)) ?

The general solution for sec(θ)=-7/(sqrt(13)) is θ=2.11189…+2pin,θ=-2.11189…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec(θ)=-7/(sqrt(13))

sec (θ) = - \frac{7}{13}

θ = 2.11189 \dots + 2 πn, θ = - 2.11189 \dots + 2 πn

Radians

θ = 2.11189 \dots + 6.28318 \dots n, θ = - 2.11189 \dots + 6.28318 \dots n

Solution steps

sec (θ) = - \frac{7}{13}

Simplify

- \frac{7}{13} : - \frac{7 13}{13}

- \frac{7}{13}

Multiply by the conjugate

\frac{13}{13}

= - \frac{7 13}{13 13}

1313 = 13

1313

Apply radical rule:

a a = a

1313 = 13

= 13

= - \frac{7 13}{13}

sec (θ) = - \frac{7 13}{13}

Apply trig inverse properties

sec (θ) = - \frac{7 13}{13}

General solutions for

sec (θ) = - \frac{7 13}{13}

sec (x) = - a \Rightarrow x = arcsec (- a) + 2 πn, x = - arcsec (- a) + 2 πn

θ = arcsec (- \frac{7 13}{13}) + 2 πn, θ = - arcsec (- \frac{7 13}{13}) + 2 πn

θ = arcsec (- \frac{7 13}{13}) + 2 πn, θ = - arcsec (- \frac{7 13}{13}) + 2 πn

Show solutions in decimal form

θ = 2.11189 \dots + 2 πn, θ = - 2.11189 \dots + 2 πn

tan (x) = - \infty

tan (2 x) = - tan (x) 2

2 sin^{2} (x) - 5 sin (x) - 12 = 0

\frac{1}{sin ( x )} = 5

tan (2 x) + tan (4 x) = 0

What is the general solution for sec(θ)=-7/(sqrt(13)) ?
The general solution for sec(θ)=-7/(sqrt(13)) is θ=2.11189…+2pin,θ=-2.11189…+2pin