What is the general solution for tan(θ)=-2/2 ?

The general solution for tan(θ)=-2/2 is θ=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ)=-2/2

tan (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + πn

Degrees

θ = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = - \frac{2}{2}

Apply rule

\frac{a}{a} = 1

tan (θ) = - 1

General solutions for

tan (θ) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

\frac{sin ( 7 8 ^{\circ} )}{14} = \frac{sin ( a )}{6}

tan (x) = (- \frac{6}{5})

cos (x^{2}) = 1

2 sin^{2} (θ) + cos (θ) - 2 = 0

sin^{3} (x) - 0.25 sin (x) = 0

What is the general solution for tan(θ)=-2/2 ?
The general solution for tan(θ)=-2/2 is θ=(3pi)/4+pin