What is the general solution for tan(pi/4+x)=2+sqrt(3) ?

The general solution for tan(pi/4+x)=2+sqrt(3) is x=1.30899…+pin-pi/4

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tan(pi/4+x)=2+sqrt(3)

tan (\frac{π}{4} + x) = 2 + 3

x = 1.30899 \dots + πn - \frac{π}{4}

Degrees

x = 3 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (\frac{π}{4} + x) = 2 + 3

Apply trig inverse properties

tan (\frac{π}{4} + x) = 2 + 3

General solutions for

tan (\frac{π}{4} + x) = 2 + 3

tan (x) = a \Rightarrow x = arctan (a) + πn

\frac{π}{4} + x = arctan (2 + 3) + πn

\frac{π}{4} + x = arctan (2 + 3) + πn

Solve

\frac{π}{4} + x = arctan (2 + 3) + πn : x = arctan (2 + 3) + πn - \frac{π}{4}

\frac{π}{4} + x = arctan (2 + 3) + πn

Move

\frac{π}{4}

to the right side

\frac{π}{4} + x = arctan (2 + 3) + πn

Subtract

\frac{π}{4}

from both sides

\frac{π}{4} + x - \frac{π}{4} = arctan (2 + 3) + πn - \frac{π}{4}

Simplify

x = arctan (2 + 3) + πn - \frac{π}{4}

x = arctan (2 + 3) + πn - \frac{π}{4}

x = arctan (2 + 3) + πn - \frac{π}{4}

Show solutions in decimal form

x = 1.30899 \dots + πn - \frac{π}{4}

3 cos (x) = 2 sin (x)

2 cos^{2} (θ) - cos (θ) = 1, 0 \leq θ \leq 2 π

tan (x) - 3 = 0, 0 \leq x \leq 2 π

1 = tan (0 + c)

4 sin^{2} (x) = 3 - 4 sin (x)

What is the general solution for tan(pi/4+x)=2+sqrt(3) ?
The general solution for tan(pi/4+x)=2+sqrt(3) is x=1.30899…+pin-pi/4