What is the general solution for -0.1429=cos(C) ?

The general solution for -0.1429=cos(C) is C=1.71418…+2pin,C=-1.71418…+2pin

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-0.1429=cos(C)

- 0.1429 = cos (C)

C = 1.71418 \dots + 2 πn, C = - 1.71418 \dots + 2 πn

Degrees

C = 98.21569 \dots^{\circ} + 36 0^{\circ} n, C = - 98.21569 \dots^{\circ} + 36 0^{\circ} n

Solution steps

- 0.1429 = cos (C)

Switch sides

cos (C) = - 0.1429

Apply trig inverse properties

cos (C) = - 0.1429

General solutions for

cos (C) = - 0.1429

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

C = arccos (- 0.1429) + 2 πn, C = - arccos (- 0.1429) + 2 πn

C = arccos (- 0.1429) + 2 πn, C = - arccos (- 0.1429) + 2 πn

Show solutions in decimal form

C = 1.71418 \dots + 2 πn, C = - 1.71418 \dots + 2 πn

sin^{2} (x) = 1 - cos (x), 0 \leq x \leq 2 π

cos (\frac{π}{4} c) = sin (2 (\frac{π}{4}))

\frac{( 1 - tanh ( 2 x ) )}{( 1 + tanh ( 2 x ) )} = 2

sin (4 θ) = 0.345

- 3 = cot^{2} (x) + 3 csc (x)

What is the general solution for -0.1429=cos(C) ?
The general solution for -0.1429=cos(C) is C=1.71418…+2pin,C=-1.71418…+2pin