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受欢迎的 三角函数 >

arcsin((900x^2-1)/(900x^2+1))=1.18

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解答

arcsin(900x2+1900x2−1​)=1.18

解答

x=301−sin(5059​)​1+sin(5059​)​​,x=−301−sin(5059​)​1+sin(5059​)​​
求解步骤
arcsin(900x2+1900x2−1​)=1.18
使用反三角函数性质
arcsin(900x2+1900x2−1​)=1.18
arcsin(x)=a⇒x=sin(a)900x2+1900x2−1​=sin(1.18)
sin(1.18)=sin(5059​)
sin(1.18)
900x2+1900x2−1​=sin(5059​)
900x2+1900x2−1​=sin(5059​)
解 900x2+1900x2−1​=sin(5059​):x=301−sin(5059​)​1+sin(5059​)​​,x=−301−sin(5059​)​1+sin(5059​)​​
900x2+1900x2−1​=sin(5059​)
在两边乘以 900x2+1
900x2+1900x2−1​=sin(5059​)
在两边乘以 900x2+1900x2+1900x2−1​(900x2+1)=sin(5059​)(900x2+1)
化简900x2−1=sin(5059​)(900x2+1)
900x2−1=sin(5059​)(900x2+1)
解 900x2−1=sin(5059​)(900x2+1):x=301−sin(5059​)​1+sin(5059​)​​,x=−301−sin(5059​)​1+sin(5059​)​​
900x2−1=sin(5059​)(900x2+1)
将 1到右边
900x2−1=sin(5059​)(900x2+1)
两边加上 1900x2−1+1=sin(5059​)(900x2+1)+1
化简900x2=sin(5059​)(900x2+1)+1
900x2=sin(5059​)(900x2+1)+1
将 sin(5059​)(900x2+1)para o lado esquerdo
900x2=sin(5059​)(900x2+1)+1
两边减去 sin(5059​)(900x2+1)900x2−sin(5059​)(900x2+1)=sin(5059​)(900x2+1)+1−sin(5059​)(900x2+1)
化简900x2−sin(5059​)(900x2+1)=1
900x2−sin(5059​)(900x2+1)=1
乘开 −sin(5059​)(900x2+1):−900sin(5059​)x2−sin(5059​)
−sin(5059​)(900x2+1)
使用分配律: a(b+c)=ab+aca=−sin(5059​),b=900x2,c=1=−sin(5059​)⋅900x2+(−sin(5059​))⋅1
使用加减运算法则+(−a)=−a=−900sin(5059​)x2−1⋅sin(5059​)
乘以:1⋅sin(5059​)=sin(5059​)=−900sin(5059​)x2−sin(5059​)
900x2−900sin(5059​)x2−sin(5059​)=1
将 sin(5059​)到右边
900x2−900sin(5059​)x2−sin(5059​)=1
两边加上 sin(5059​)900x2−900sin(5059​)x2−sin(5059​)+sin(5059​)=1+sin(5059​)
化简900x2−900sin(5059​)x2=1+sin(5059​)
900x2−900sin(5059​)x2=1+sin(5059​)
分解 900x2−900sin(5059​)x2:900(1−sin(5059​))x2
900x2−900sin(5059​)x2
改写为=1⋅900x2−900x2sin(5059​)
因式分解出通项 900x2=900x2(1−sin(5059​))
900(1−sin(5059​))x2=1+sin(5059​)
两边除以 900(1−sin(5059​))
900(1−sin(5059​))x2=1+sin(5059​)
两边除以 900(1−sin(5059​))900(1−sin(5059​))900(1−sin(5059​))x2​=900(1−sin(5059​))1​+900(1−sin(5059​))sin(5059​)​
化简
900(1−sin(5059​))900(1−sin(5059​))x2​=900(1−sin(5059​))1​+900(1−sin(5059​))sin(5059​)​
化简 900(1−sin(5059​))900(1−sin(5059​))x2​:x2
900(1−sin(5059​))900(1−sin(5059​))x2​
数字相除:900900​=1=1−sin(5059​)(−sin(5059​)+1)x2​
约分:1−sin(5059​)=x2
化简 900(1−sin(5059​))1​+900(1−sin(5059​))sin(5059​)​:900(1−sin(5059​))1+sin(5059​)​
900(1−sin(5059​))1​+900(1−sin(5059​))sin(5059​)​
因为分母相等,所以合并分式: ca​±cb​=ca±b​=900(1−sin(5059​))1+sin(5059​)​
x2=900(1−sin(5059​))1+sin(5059​)​
x2=900(1−sin(5059​))1+sin(5059​)​
x2=900(1−sin(5059​))1+sin(5059​)​
对于 x2=f(a) 解为 x=f(a)​,−f(a)​
x=900(1−sin(5059​))1+sin(5059​)​​,x=−900(1−sin(5059​))1+sin(5059​)​​
900(1−sin(5059​))1+sin(5059​)​​=301−sin(5059​)​1+sin(5059​)​​
900(1−sin(5059​))1+sin(5059​)​​
使用根式运算法则: 假定 a≥0,b≥0=900(−sin(5059​)+1)​1+sin(5059​)​​
使用根式运算法则: 假定 a≥0,b≥0900(−sin(5059​)+1)​=900​−sin(5059​)+1​=900​−sin(5059​)+1​1+sin(5059​)​​
900​=30
900​
因式分解数字: 900=302=302​
使用根式运算法则: 302​=30=30
=30−sin(5059​)+1​1+sin(5059​)​​
=301−sin(5059​)​1+sin(5059​)​​
−900(1−sin(5059​))1+sin(5059​)​​=−301−sin(5059​)​1+sin(5059​)​​
−900(1−sin(5059​))1+sin(5059​)​​
化简 900(1−sin(5059​))1+sin(5059​)​​:30−sin(5059​)+1​1+sin(5059​)​​
900(1−sin(5059​))1+sin(5059​)​​
使用根式运算法则: 假定 a≥0,b≥0=900(−sin(5059​)+1)​1+sin(5059​)​​
使用根式运算法则: 假定 a≥0,b≥0900(−sin(5059​)+1)​=900​−sin(5059​)+1​=900​−sin(5059​)+1​1+sin(5059​)​​
900​=30
900​
因式分解数字: 900=302=302​
使用根式运算法则: 302​=30=30
=30−sin(5059​)+1​1+sin(5059​)​​
=−30−sin(5059​)+1​sin(5059​)+1​​
=−301−sin(5059​)​1+sin(5059​)​​
x=301−sin(5059​)​1+sin(5059​)​​,x=−301−sin(5059​)​1+sin(5059​)​​
x=301−sin(5059​)​1+sin(5059​)​​,x=−301−sin(5059​)​1+sin(5059​)​​
x=301−sin(5059​)​1+sin(5059​)​​,x=−301−sin(5059​)​1+sin(5059​)​​

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