What is the general solution for sin(θ)=0.12 ?

The general solution for sin(θ)=0.12 is θ=0.12028…+2pin,θ=pi-0.12028…+2pin

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sin(θ)=0.12

sin (θ) = 0.12

θ = 0.12028 \dots + 2 πn, θ = π - 0.12028 \dots + 2 πn

Degrees

θ = 6.89210 \dots^{\circ} + 36 0^{\circ} n, θ = 173.10789 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = 0.12

Apply trig inverse properties

sin (θ) = 0.12

General solutions for

sin (θ) = 0.12

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (0.12) + 2 πn, θ = π - arcsin (0.12) + 2 πn

θ = arcsin (0.12) + 2 πn, θ = π - arcsin (0.12) + 2 πn

Show solutions in decimal form

θ = 0.12028 \dots + 2 πn, θ = π - 0.12028 \dots + 2 πn

cos (x) tan (x) - sin^{2} (x) = 0

t, y^{11} + 9 y = 18 cos (3 t)

tan (x) = \frac{0.75}{6}

2 sec (x) - 2 = 0

(tan (x)) (sin^{2} (x) - a) (sec (x) - a) = 0

What is the general solution for sin(θ)=0.12 ?
The general solution for sin(θ)=0.12 is θ=0.12028…+2pin,θ=pi-0.12028…+2pin