What is the general solution for solvefor x,y+arctan(y/x)=0 ?

The general solution for solvefor x,y+arctan(y/x)=0 is x= y/(tan(-y))

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solvefor x,y+arctan(y/x)=0

solve for

x, y + arctan (\frac{y}{x}) = 0

x = \frac{y}{tan ( - y )}

Solution steps

y + arctan (\frac{y}{x}) = 0

Move

y

to the right side

y + arctan (\frac{y}{x}) = 0

Subtract

y

from both sides

y + arctan (\frac{y}{x}) - y = 0 - y

Simplify

arctan (\frac{y}{x}) = - y

arctan (\frac{y}{x}) = - y

Apply trig inverse properties

arctan (\frac{y}{x}) = - y

arctan (x) = a \Rightarrow x = tan (a)

\frac{y}{x} = tan (- y)

\frac{y}{x} = tan (- y)

Solve

\frac{y}{x} = tan (- y) : x = \frac{y}{tan ( - y )}; y \neq = - πn

\frac{y}{x} = tan (- y)

Multiply both sides by

x

\frac{y}{x} = tan (- y)

Multiply both sides by

x

\frac{y}{x} x = tan (- y) x

Simplify

y = tan (- y) x

y = tan (- y) x

Switch sides

tan (- y) x = y

Divide both sides by

tan (- y); y \neq = - πn

tan (- y) x = y

Divide both sides by

tan (- y); y \neq = - πn

\frac{tan ( - y ) x}{tan ( - y )} = \frac{y}{tan ( - y )}; y \neq = - πn

Simplify

x = \frac{y}{tan ( - y )}; y \neq = - πn

x = \frac{y}{tan ( - y )}; y \neq = - πn

x = \frac{y}{tan ( - y )}

tan (θ) = - 1, 0 \leq θ \leq 2 π

0.85 = \frac{1 - sin ( x )}{1 + sin ( x )}

sin (2 x) - \frac{2}{2} = 0

y, z = x sin (x y)

sin (θ) = 0.12

What is the general solution for solvefor x,y+arctan(y/x)=0 ?
The general solution for solvefor x,y+arctan(y/x)=0 is x= y/(tan(-y))