What is the general solution for cos(θ)=0.6798,0<= θ<= 360 ?

The general solution for cos(θ)=0.6798,0<= θ<= 360 is θ=0.82330…,θ=5.45987…

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cos(θ)=0.6798,0<= θ<= 360

cos (θ) = 0.6798, 0^{\circ} \leq θ \leq 36 0^{\circ}

θ = 0.82330 \dots, θ = 5.45987 \dots

Solution steps

cos (θ) = 0.6798, 0^{\circ} \leq θ \leq 36 0^{\circ}

Apply trig inverse properties

cos (θ) = 0.6798

General solutions for

cos (θ) = 0.6798

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (0.6798) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (0.6798) + 36 0^{\circ} n

θ = arccos (0.6798) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (0.6798) + 36 0^{\circ} n

Solutions for the range

0 \leq θ \leq 36 0^{\circ}

θ = 0.82330 \dots, θ = 5.45987 \dots

\frac{2 sin ( x ) cos ( x )}{cos ( x )} = 1

csc (3 θ) = sec (1 5^{\circ})

2 cot^{2} (x) + tan (x) = cot (x)

sin (2 x) = sin (\frac{π}{2} - x)

tan (X) = 1

What is the general solution for cos(θ)=0.6798,0<= θ<= 360 ?
The general solution for cos(θ)=0.6798,0<= θ<= 360 is θ=0.82330…,θ=5.45987…