What is the general solution for sin^2(x)+sin^2(x)=cos^2(x) ?

The general solution for sin^2(x)+sin^2(x)=cos^2(x) is x=-0.61547…+pin,x=0.61547…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)+sin^2(x)=cos^2(x)

Solution

sin^{2} (x) + sin^{2} (x) = cos^{2} (x)

Solution

x = - 0.61547 \dots + πn, x = 0.61547 \dots + πn

Degrees

x = - 35.26438 \dots^{\circ} + 18 0^{\circ} n, x = 35.26438 \dots^{\circ} + 18 0^{\circ} n

Solution steps

sin^{2} (x) + sin^{2} (x) = cos^{2} (x)

Subtract

cos^{2} (x)

from both sides

2 sin^{2} (x) - cos^{2} (x) = 0

Factor

2 sin^{2} (x) - cos^{2} (x) : (2 sin (x) + cos (x)) (2 sin (x) - cos (x))

2 sin^{2} (x) - cos^{2} (x)

Rewrite

2 sin^{2} (x) - cos^{2} (x)

(2 sin (x))^{2} - cos^{2} (x)

2 sin^{2} (x) - cos^{2} (x)

Apply radical rule:

a = (a)^{2}

2 = (2)^{2}

= (2)^{2} sin^{2} (x) - cos^{2} (x)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m}

(2)^{2} sin^{2} (x) = (2 sin (x))^{2}

= (2 sin (x))^{2} - cos^{2} (x)

= (2 sin (x))^{2} - cos^{2} (x)

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 sin (x))^{2} - cos^{2} (x) = (2 sin (x) + cos (x)) (2 sin (x) - cos (x))

= (2 sin (x) + cos (x)) (2 sin (x) - cos (x))

(2 sin (x) + cos (x)) (2 sin (x) - cos (x)) = 0

Solving each part separately

2 sin (x) + cos (x) = 0 or 2 sin (x) - cos (x) = 0

2 sin (x) + cos (x) = 0 : x = arctan (- \frac{2}{2}) + πn

2 sin (x) + cos (x) = 0

Rewrite using trig identities

2 sin (x) + cos (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{2 sin ( x ) + cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

\frac{2 sin ( x )}{cos ( x )} + 1 = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

2 tan (x) + 1 = 0

2 tan (x) + 1 = 0

Move

1

to the right side

2 tan (x) + 1 = 0

Subtract

1

from both sides

2 tan (x) + 1 - 1 = 0 - 1

Simplify

2 tan (x) = - 1

2 tan (x) = - 1

Divide both sides by

2

2 tan (x) = - 1

Divide both sides by

2

\frac{2 tan ( x )}{2} = \frac{- 1}{2}

Simplify

\frac{2 tan ( x )}{2} = \frac{- 1}{2}

Simplify

\frac{2 tan ( x )}{2} : tan (x)

\frac{2 tan ( x )}{2}

Cancel the common factor:

2

= tan (x)

Simplify

\frac{- 1}{2} : - \frac{2}{2}

\frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

Rationalize

- \frac{1}{2} : - \frac{2}{2}

- \frac{1}{2}

Multiply by the conjugate

\frac{2}{2}

= - \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

Apply radical rule:

a a = a

22 = 2

= 2

= - \frac{2}{2}

= - \frac{2}{2}

tan (x) = - \frac{2}{2}

tan (x) = - \frac{2}{2}

tan (x) = - \frac{2}{2}

Apply trig inverse properties

tan (x) = - \frac{2}{2}

General solutions for

tan (x) = - \frac{2}{2}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- \frac{2}{2}) + πn

x = arctan (- \frac{2}{2}) + πn

2 sin (x) - cos (x) = 0 : x = arctan (\frac{2}{2}) + πn

2 sin (x) - cos (x) = 0

Rewrite using trig identities

2 sin (x) - cos (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{2 sin ( x ) - cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

\frac{2 sin ( x )}{cos ( x )} - 1 = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

2 tan (x) - 1 = 0

2 tan (x) - 1 = 0

Move

1

to the right side

2 tan (x) - 1 = 0

Add

1

to both sides

2 tan (x) - 1 + 1 = 0 + 1

Simplify

2 tan (x) = 1

2 tan (x) = 1

Divide both sides by

2

2 tan (x) = 1

Divide both sides by

2

\frac{2 tan ( x )}{2} = \frac{1}{2}

Simplify

\frac{2 tan ( x )}{2} = \frac{1}{2}

Simplify

\frac{2 tan ( x )}{2} : tan (x)

\frac{2 tan ( x )}{2}

Cancel the common factor:

2

= tan (x)

Simplify

\frac{1}{2} : \frac{2}{2}

\frac{1}{2}

Multiply by the conjugate

\frac{2}{2}

= \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

Apply radical rule:

a a = a

22 = 2

= 2

= \frac{2}{2}

tan (x) = \frac{2}{2}

tan (x) = \frac{2}{2}

tan (x) = \frac{2}{2}

Apply trig inverse properties

tan (x) = \frac{2}{2}

General solutions for

tan (x) = \frac{2}{2}

tan (x) = a \Rightarrow x = arctan (a) + πn

x = arctan (\frac{2}{2}) + πn

x = arctan (\frac{2}{2}) + πn

Combine all the solutions

x = arctan (- \frac{2}{2}) + πn, x = arctan (\frac{2}{2}) + πn

Show solutions in decimal form

x = - 0.61547 \dots + πn, x = 0.61547 \dots + πn

Popular Examples

2sin(2t)=0

2 sin (2 t) = 0

cos(x)-0.5=0

cos (x) - 0.5 = 0

cos(x)= 6/14

cos (x) = \frac{6}{14}

solvefor x,sec(x)=2 solve for

x, sec (x) = 2

sin(θ)=sin(-2/3 pi)

sin (θ) = sin (- \frac{2}{3} π)

Frequently Asked Questions (FAQ)

What is the general solution for sin^2(x)+sin^2(x)=cos^2(x) ?
The general solution for sin^2(x)+sin^2(x)=cos^2(x) is x=-0.61547…+pin,x=0.61547…+pin