What is the general solution for sin(x)=(123sin(70))/(184.5) ?

The general solution for sin(x)=(123sin(70))/(184.5) is x=0.67700…+360n,x=180-0.67700…+360n

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sin(x)=(123sin(70))/(184.5)

sin (x) = \frac{123 sin ( 7 0 ^{\circ} )}{184.5}

x = 0.67700 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.67700 \dots + 36 0^{\circ} n

Radians

x = 0.67700 \dots + 2 πn, x = π - 0.67700 \dots + 2 πn

Solution steps

sin (x) = \frac{123 sin ( 7 0 ^{\circ} )}{184.5}

Apply trig inverse properties

sin (x) = \frac{123 sin ( 7 0 ^{\circ} )}{184.5}

General solutions for

sin (x) = \frac{123 sin ( 7 0 ^{\circ} )}{184.5}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

x = arcsin (\frac{123 sin ( 7 0 ^{\circ} )}{184.5}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{123 sin ( 7 0 ^{\circ} )}{184.5}) + 36 0^{\circ} n

x = arcsin (\frac{123 sin ( 7 0 ^{\circ} )}{184.5}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{123 sin ( 7 0 ^{\circ} )}{184.5}) + 36 0^{\circ} n

Show solutions in decimal form

x = 0.67700 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.67700 \dots + 36 0^{\circ} n

cot^{2} (θ) = cot (θ), 0 \leq θ \leq 2 π

cos (x) = \frac{9}{19}

cos (α) = \frac{5}{3}

2 - 3 sin (x) - cos (2 x) = 0

cos (2 θ) = \frac{1}{4}

What is the general solution for sin(x)=(123sin(70))/(184.5) ?
The general solution for sin(x)=(123sin(70))/(184.5) is x=0.67700…+360n,x=180-0.67700…+360n