What is the general solution for solvefor x,cos(x)=cos(p) ?

The general solution for solvefor x,cos(x)=cos(p) is x=arccos(cos(p))+2pin,x=-arccos(cos(p))+2pin

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solvefor x,cos(x)=cos(p)

solve for

x, cos (x) = cos (p)

x = arccos (cos (p)) + 2 πn, x = - arccos (cos (p)) + 2 πn

Solution steps

cos (x) = cos (p)

Apply trig inverse properties

cos (x) = cos (p)

General solutions for

cos (x) = cos (p)

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (cos (p)) + 2 πn, x = - arccos (cos (p)) + 2 πn

x = arccos (cos (p)) + 2 πn, x = - arccos (cos (p)) + 2 πn

cot (a) - 1 = 0

csc (θ) = - \frac{3}{5}

cos^{2} (β) = \frac{16}{25}, 0 \leq β \leq 2 π

arctan (x) + arctan (\frac{x}{2}) = 90

6 sin (c) + 8 = 0

What is the general solution for solvefor x,cos(x)=cos(p) ?
The general solution for solvefor x,cos(x)=cos(p) is x=arccos(cos(p))+2pin,x=-arccos(cos(p))+2pin